A 18 mL sample of gas has a temperature of 86 ˚C and a pressure of 6 atm. What temperature would be needed for the same amount of gas to fit into a 300 mL flask at standard pressure? (at constant moles)

Answer : The temperature needed for the same amount of gas would be, 997.2 K

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

where,

= initial pressure of gas = 6 atm

= final pressure of gas = 1 atm

= initial volume of gas = 18 mL

= final volume of gas = 300 mL

= initial temperature of gas =

= final temperature of gas = ?

Now put all the given values in the above equation, we get:

Thus, the temperature needed for the same amount of gas would be, 997.2 K

weight of any object is given by

w = m*g

where m is mass of the object and g is the acceleration due to gravity.

for earth the value of g is 9.8 m/s^2 so

w=117.6 n m=12 g=?

117.6=12g => g=9.8 m/s^2

which is the force of gravity on earth.