Using what you have learned about the three forms of writing chemical equations, classify each of the presented equations as either a molecular equation, a complete ionic equation, or a net ionic equation.

(a) Ca2+(aq) + SO42−(aq)→ CaSO4(s)
(b) CuSO4(aq) + 2KOH(aq)→ Cu(OH)2(s) + K2SO4(aq)
(c) Ba2+ (aq) + SO42−(aq)→ BaSO4(s)
(d) Ag+(aq) + NO3−(aq) + I−(aq)→ AgI(s) + NO3−(aq)

Explanation:

Molecular equation: Chemical equation in which molecular formula of reactants and products are written

Complete ionic equation:Chemical equation in which ionic from if reactants reactants and products are written along with spectator ions (ions present on both sides of equation).

Net ionic equation :Chemical equation in which only ions of those reactant are written which giving product without  spectator ions (ions present on both sides of equation).

(a)

net ionic equation.

(b)

Molecular equation

(c)

Net ionic equation.

(d)

Complete ionic equation

93.2 ml + 3920 ml = 4013 ml total  

(93.2 ml) * (2.03 m) / (4013 ml) = 0.0471 m

the volume in in l of the diluted solution would be 0.0471 m.

its mg hope this