What volume (in L) of a 2.46 M.
magnessium nitrate (Mg(NO3)2)
solution would be needed to make
275 mL of a 0.758 M solution by
dilution?

0.0847L

Explanation:

The following data were obtained from the question:

C1 = 2.46 M

V1 =?

C2 = 0.758 M

V2 = 275 mL = 275/1000 = 0.275L

Using the dilution formula C1V1 = C2V2, we can confidently calculate the volume of the original solution as follows:

C1V1 = C2V2

2.46 x V1 = 0.758 x 0.275

Divide both side by 2.46

V1 = (0.758 x 0.275) /2.46

V1 = 0.0847L

Therefore, 0.0847L is needed