Aluminum nitrite and ammonium cloride react to form aluminium chloride. nitrogen and water. what mass of alluminum chloride is present of 43g of ammonium nitrite have reacted completely

35.7 g of NH₄Cl

Explanation:

The reaction is:

Al(NO₂)₃ +  3NH₄Cl → AlCl₃ + 3N₂ + 6H₂O

Ratio is 3:1. 3 mol of ammoium chloride react to produce 1 mol of chloride

We convert the mass of ammoium chloride to moles:

43 g . 1 mol/ 53.45 g = 0.804 moles

(0.804 . 1) / 3 = 0.268 moles of AlCl₃ are formed

Let's convert the moles to mass → 0.268 mol . 133.33 g/1mol = 35.7 g

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."

the answer would be c