A sample of steam with a mass of 0.530 g at a temperature of 100 ∘C condenses into an insulated container holding 4.20 g of water at 6.0 ∘C. (For water, ΔH∘vap=40.7 kJ/mol and Cwater=4.18 J/(g⋅∘C).)

4.66C

Explanation:

q1 heat gained by water = mcdeltaT

massH2O x specific heat water x (Tfinal-Tinitial). T f is the final Temperature and Ti is the initial Temperature.

q1 = 0.530g x 4.184 J/g*C x (Tfinal - 100.0) = 0.022

q2 = heat lost by steam in converting steam (g) at 100.0 C to liquid at 100.0 C = mass x delta H.

q2 = 4.20g x 40.7 (Tfinal - 100.0) = 1.71

q3 = heat lost with 4.20 g (from the steam conversion) water moving from 6.0 C to final T.

q3 = 4.20g x 4.184 J/g C x (t final - 6.0) =2.93

Ti is 6.0

t final= q1 + q2 + q3

0.022 + 1.71 + 2.93 = 4.66 C

Tfinal= 4.66C

oh it is true if thats what you are asking

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !