Balance the chemical equation given below, and calculate the volume of nitrogen monoxide gas produced when 8.00 g of ammonia is reacted with 12.0 g of oxygen at 25°C? The density of nitrogen monoxide at 25°C is 1.23 g/L.___ NH3(g) + ___ O2(g) ? ___ NO(g) + ___ H2O(l)A) 4.88LB) 7.38LC) 11.5LD) 17.3LE) 19.2L

The volume of NO is 7.32 L  (option B 7.28L is the closest to this)

Explanation:

Step 1: Data

Mass of ammonia = 8.00 grams

Mass of oxygen = 12.0 grams

Temperature = 25.0 °C

Density of NO = 1.23 g/L

Step 2: The balanced equation

4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(l)

Step 3: Calculate moles ammonia

Moles ammonia = 8.00 grams / 17.03 g/mol

Moles ammonia = 0.470 moles

Step 4: Calculate moles oxygen

Moles O2 = 12.0 grams / 32.0 g/mol

Moles O2 = 0.375 moles

Step 5: Calculate limiting reactant

For 4 moles NH3 we need 5 moles O2 to produce 4 moles NO and 6 moles H2O

O2 is the limiting reactant. It will completely be consumed (0.375 moles).

NH3 is in excess. There react 4/5*0.375 moles = 0.300 moles

There remain 0.470 - 0.300 = 0.170 moles NH3

Step 6: Calculate moles NO

For 4 moles NH3 we need 5 moles O2 to produce 4 moles NO and 6 moles H2O

For 0.375 moles O2 we'll have 0.300 moles NO produced

Step 7: calculate mass NO

Mass NO = moles * molar mass

Mass NO = 0.300 moles * 30.01 g/mol

Mass NO = 9.003 grams

Step 8: Calculate volume NO

Volume NO = mass NO / density

Volume NO = 9.003 grams / 1.23 g/L

Volume NO = 7.32 L

The volume of NO is 7.32 L  (option B 7.28L is the closest to this)

each  column  of the  table  is called a group. elements in a group share similar properties. groups are  read  from  top  to  bottom. metal. metalloid. nonmetal. solid. liquid. gas. fe. hg. o.  2. 3. 4. 5. 6. 7. 8. 9.  2. beryllium. 9.012. 4.  sodium. 22.990.  11. 3.  magnesium. 24.305.  12.  potassium. 39.098.  19. 4.  calcium. 40.078.  20. i guess  i