The rate law is first-order in N2O5. At 45 °C the rate constant is 6.08 x 10–4 s–1. What is the rate of the reaction when [N2O5] = 0.100 M, and what happens to the rate when the concentration of N2O5 is doubled to 0.200 M?

Explanation:

Rate constant = 6.08 x 10–4 s–1

What is the rate of the reaction when [N2O5] = 0.100 M..?

A first-order reaction depends on the concentration of one reactant, and the rate law is:

r= −dA / dt = k[A]

Rate of reaction = k [ A ]

where [A] = 0.100 M

Rate of reaction = (6.08 x 10–4) x 0.100

Rate of reaction = 6.08 x 10–5 Ms–1

what happens to the rate when the concentration of N2O5 is doubled to 0.200 M?

Rate of reaction = k [ A ]

[A] = 0.200

Rate of reaction = (6.08 x 10–4) x 0.200

Rate of reaction = 1.216 x 10–4 Ms–1

The rate of the reaction increases to 1.216 x 10–4 Ms–1

- calcium has greater affinity to bond with electron receptors than hydrogen does and hence, it has the ability to replace hydrogen in most of its compounds.

- lithium has 2 valence electrons in the product because it can make only 1 bond with hydrogen. beryllium has 4 valence electrons in the product because it can only make 2 bonds. it has fewer electrons than neon and can react with electron donors. each hydrogen has 2 valence electrons, the same as helium.

- the covalent bond formed between carbon and hydrogen is polar because carbon is more electronegative than hydrogen and it attracts the bonded electron pair closer to itself, thus giving hydrogen a partial positive charge.

- a hydrogen bond is a relatively weak bond that hydrogen atoms make with the electronegative atoms nitrogen, oxygen or fluorine.

so the best choice is a.) 2 calcium (ca) atoms

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml