Some ethylene glycol, , is added to your car’s cooling system along with 5.0 kg of water.

a. If the freezing point of the water–glycol solution is −14.0 °C, what mass of must have been added?
b. What is the boiling point of the coolant mixture? Kb(H20) = 0.52 degrees celcius kg mol^-1.

a) 2.333 kg of glycol was added in car's cooling system along with 5.0 kg of water.

b) The boiling point of coolant mixture is 103.91°C.

Explanation:

a)

where,

= freezing point of solution

T = freezing point of solvent

=depression in freezing point  

= freezing point constant  

m = molality  =

we have :

Mass of glycol = x

Mass of solvent = 5.0kg

Molality of the solution ,m=

=1.86°C/m ,

x = 2,333.33 g

2,333.33 = 2.3333 kg ( g = 0.001 kg)

2.333 kg of glycol was added in car's cooling system along with 5.0 kg of water.

b)

where,

=elevation in boiling point =  

= boiling point constant  

m = molality

we have :

=0.52°C/m ,

Molality of the solution ,m=

Boiling point of pure water = T =  100°C

Boiling point of solution =

The boiling point of coolant mixture is 103.91°C.

d.) the average kinetic energy of the gas particles is greater in container b because its particles move faster.