Duncan takes a break from studying and goes to the gym to swim laps. If swimming burns 6.55×105 calcal per hour, how many kilojoules does swimming burn in that same amount of time? In other words, convert 6.55×105 calcal to kilojoules

2.751x10^3KJ

Explanation:

The following were obtained from the question given:

Duncan burns 6.55×10^5 calcal per hour.

1 calorie = 4.2J

6.55×10^5 calories = 6.55×10^5 x 4.2 = 2.751x10^6J

Now we divide by 1000 to expressed in KJ i.e

2.751x10^6/1000 = 2.751x10^3KJ

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)

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