Chemistry, 27.02.2020 20:13 SKYBLUE1015
Some SbCl5 is allowed to dissociate into SbCl3 and Cl2 at 521 K. At equilibrium, [SbCl5] = 0.195 M, and [SbCl3] = [Cl2] = 6.98×10-2 M. Additional SbCl5 is added so that [SbCl5]new = 0.370 M and the system is allowed to once again reach equilibrium.
SbCl5(g) <-> SbCl3(g) + Cl2(g) K = 2.50×10-2 at 521 K
(a) In which direction will the reaction proceed to reach equilibrium? to the right to the left
(b) What are the new concentrations of reactants and products after the system reaches equilibrium?
[SbCl5] = M
[SbCl3] = ___M
[Cl2] = ___M
Answers: 2
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