Calculate the number of atoms of each element and the total number of atoms contained in 2.50 moles of Al2(SO4)3.

15.05 * 10^23 atoms are present in 2.50moles of Al2(SO4)3

Explanation:

To solve this question, the Avogadro equation is used.

Number of moles (n) = number of atoms (N) / Avogadro number.

n = N / 6.02*10^23

So therefore;

2.50moles = N / 6.02* 10^23

N = 6.02* 10^23 * 2.50

N = 15.05* 10^23 atoms.

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

well in order to answer this question you have to provide more information < 3