The rate constant of a particular first order reaction is 5.45 x 10^-2 sec^-1 at 40.0 oC. What is the rate constant of this reaction at 65.0 oC if the energy of activation, Ea for this reaction is 65.5 kJ/mol

The rate constant for the reaction at 65°C is

Explanation:

To calculate rate constant at 65°C of the reaction, we use Arrhenius equation, which is:

where,

= equilibrium constant at 65°C = ?

= equilibrium constant at 40°C =

= Activation energy of the reaction = 65.5 kJ/mol = 65500 J/mol    (Conversion factor:  1 kJ = 1000 J)

R = Gas constant = 8.314 J/mol K

= initial temperature =

= final temperature =

Putting values in above equation, we get:

Hence, the rate constant for the reaction at 65°C is

hey there!

mass = 6.75 g

volume =   9 cm³

therefore:

d = mass / volume

d   = 6.75 / 9

d = 0.7 g/cm³

answer b