A student titrates a 10.0 mL sample of H2O2. The titration required a 22.25 mL of 0.195 M KMnO4. Calculate the concentration (molarity) of the H2O2. Show all work.

See explanation below

Explanation:

In this case, we first need to write the general equation of the peroxide and the manganate which is:

H2O2 + KMnO4 > MnO2 + KOH + O2 + H2O

Now, we need to balance this. We can balance through REDOX, oxidation number or ion electron mode. Either method you use, the balanced reaction is the following:

3H2O2 + 2KMnO4 > 2MnO2 + 2KOH + 3O2 + 2H2O

Now that we have this, we can say that:

3 moles H2O2 = 2 moles KMnO4

moles can be expressed in terms of concentration and volume

n = M*V

Replacing this, above we have:

3 M* V H2O2 = 2 M* V KMnO4

We have volume and concentration of permanganate, and volume of peroxyde, so we can solve for the concentration:

M H2O2 = 2 * M * V KMnO4 / 3 V H2O2

Replacing the values we have:

M H2O2 = 2 * 0.195 * 22.25 / 3 * 10

M H2O2 = 0.283 M

conduction is the transfer of thermal energy (heat in transfer) due to collisions between the molecules in the object. collisions between adjacent atoms and molecules transfer kinetic energy from the warmer to the cooler object. the objects must be in physical contact.

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