Chemistry, 26.02.2020 17:56 babyshazi

Calculate the number of moles of HI that are at equilibrium with 1.39 mol of H2 and 1.39 mol of I2 in a 5.00−L flask at 448 °C. H2+I2⇌2HI Kc=50.2 at 448°C

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Answer from: Jimenezmiranda

The equilibrium moles of HI is 2.168 moles

Explanation:

We are given:

Initial moles of hydrogen gas = 1.39 moles

Initial moles of iodine = 1.39 moles

Molarity is calculated by using the formula:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Volume of the container = 5.00 L

The given chemical equation follows:

$H_2+I_2\rightleftharpoons 2HI$

Initial: 1.39 1.39

At eqllm: 1.39-x 1.39-x 2x

The expression of K_c for above equation follows:

$K_c=\frac{[HI]^2}{[I_2][H_2]}$

We are given:

K_c=50.2

$[HI]_{eq}=\frac{2x}{5.00}$

$[H_2]_{eq}=\frac{(1.39-x)}{5.00}$

$[I_2]_{eq}=\frac{(1.39-x)}{5.00}$

Putting values in above expression, we get:

$50.2=\frac{(2x/5)^2}{((1.39-x)/5)\times ((1.39-x)/5)}\\\\x=1.084,1.94$

Neglecting the value of x = 1.94 because equilibrium concentration cannot be greater than initial concentration

So, equilibrium moles of $HI=2x=(2\times 1.084)=2.168moles$

Hence, the equilibrium moles of HI is 2.168 moles

Answer from: Quest

assuming that your periodic table has eighteen columns, you should highlight the four elements in the third column from the left of the table.

explanation

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the $3d$ have energy higher than those in the $4 s$ orbital while lower than those of the $4 p$ orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the $4s$ orbital is therefore filled right after $3p$ orbitals and before $3 d$ orbitals.

potassium has electron configuration $[\text{ar}] 4 s^{1}$ and calcium $[\text{ar}] 4 s^{2}$ . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration $[\text{ar}] 4 s^{2} \; 3d^{1}$ and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the $ns^{2} \; (n-1) p^{1}$ and should be highlighted as well.

Answer from: Quest

answer: mole of the gas

answer: mole of the gasexplanation:

answer: mole of the gasexplanation: this is because 1 mole of a gas is 22.4dm³, which is use in ideal gas

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Calculate the number of moles of HI that are at equilibrium with 1.39 mol of H2 and 1.39 mol of I2 i...