A concentration cell consists of two Sn/Sn2+ half-cells. The cell has a potential of 0.10 V at 25 ºC. What is the ratio of the Sn2+ concentrations in the two half-cells?

The ratio of  in the cell is

Explanation:

The half reactions for the cell is:  

Oxidation half reaction (anode):  

Reduction half reaction (cathode):  

In this case, the cathode and anode both are same. So, will be equal to zero.

To calculate cell potential of the cell, we use the equation given by Nernst, which is:

where,

n = number of electrons in oxidation-reduction reaction = 2

= 0.10 V

 = ?

Putting values in above equation, we get:

Hence, the ratio of  in the cell is

1 a

2 d

3 a

4 c

explanation:

in the analysis of systems that involve fluid flow, we frequently encounter the combination of properties u and pv.