Chemistry, 25.02.2020 23:57 sylaspotter707

Moles/Mass/Molecules Practice Problem Worksheet

Complete the following problems:

1. Convert 11.03 moles of calcium nitrate to grams.

2. How many molecules are contained in 103.4g of sulfuric acid?

3. 3.25 x 1024 molecules of dinitrogen pentoxide would be how many moles?

4. What would be the mass of 9.03 x 1021 molecules of hydrobromic acid?

5. A sample of iron (III) chloride has a mass of 26.29g. How many moles would this be?

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Answers

Answer from: lildeb8593

1. Converting 11.03 moles of calcium nitrate to grams gives 1,809.89 grams.

2. The number of molecules that are contained in 103.4 g of sulfuric acid is $6.35 \times 10^{23}$ molecules.

3. Converting $3.25 \times 10^{24}$ molecules of dinitrogen pentoxide to moles is equal to 5.3987 moles.

4. The mass of $9.03 \times 10^{21}$ molecules of hydrobromic acid is 1.2135 grams.

5. The number of moles contained in 26.29 g of iron (III) chloride is 0.1621 moles.

Given the following data:

Number of moles of calcium nitrate = 11.03 molesMass of sulfuric acid = 103.4 gramsNumber of molecules of dinitrogen pentoxide = $3.25 \times 10^{24 }$ Number of molecules of hydrobromic acid = $9.03 \times 10^{21 }$ Mass of iron (III) chloride = 26.29 grams

Scientific data:

The molar mass of calcium nitrate = 46.07 g/mol.The molar mass of sulfuric acid = 98.079 g/mol.The molar mass of hydrobromic acid = 80.91 g/mol.The molar mass of iron (III) chloride = 162.2 g/mol.Avogadro's number = $6.02 \times 10^{23}$

1. To convert 11.03 moles of calcium nitrate to grams:

$Mass = Number\;of\;moles \times molar\;mass\\\\Mass = 11.03 \times 164.088$

Mass of calcium nitrate = 1,809.89 grams.

2. To calculate how many molecules are contained in 103.4 g of sulfuric acid:

First of all, we would determine the number of moles contained in 103.4 g of sulfuric acid.

$Number\;of\;moles = \frac{mass}{molar\;mass}\\\\Number\;of\;moles = \frac{103.4}{98.079}$

Number of moles = 1.0543 moles

By stoichiometry:

1 mole of sulfuric acid = $6.02 \times 10^{23}$ molecules

1.0543 mole of sulfuric acid = X molecules

Cross-multiplying, we have:

$X = 1.0543 \times 6.02 \times 10^{23}$

X = $6.35 \times 10^{23}$ molecules

3. To convert $3.25 \times 10^{24}$ molecules of dinitrogen pentoxide to moles:

By stoichiometry:

1 mole of dinitrogen pentoxide = $6.02 \times 10^{23}$ molecules

X mole of dinitrogen pentoxide = $3.25 \times 10^{24}$ molecules

Cross-multiplying, we have:

$X=\frac{3.25 \times 10^{24}}{6.02 \times 10^{23}}$

X = 5.3987 moles

4. To calculate the mass of $9.03 \times 10^{21}$ molecules of hydrobromic acid:

First of all, we would determine the number of moles contained in $9.03 \times 10^{21}$ molecules of hydrobromic acid.

By stoichiometry:

1 mole of hydrobromic acid = $6.02 \times 10^{23}$ molecules

X mole of hydrobromic acid = $9.03 \times 10^{21}$ molecules

Cross-multiplying, we have:

$X=\frac{9.03 \times 10^{21} }{6.02 \times 10^{23}}$

X = 0.015 moles

$Mass = Number\;of\;moles \times molar\;mass\\\\Mass = 0.015 \times 80.91$

Mass of hydrobromic acid = 1.2135 grams.

5. To calculate the number of moles contained in 26.29 g of iron (III) chloride:

$Number\;of\;moles = \frac{mass}{molar\;mass}\\\\Number\;of\;moles = \frac{26.29}{162.2}$

Number of moles = 0.1621 moles.

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Answer from: talyku7131

Explanation:

1) Convert 11.03 moles of calcium nitrate to grams.

Given data:

Number of moles = 11.03 mol

Mass of calcium nitrate = ?

Solution:

Formula:

Number of moles = mass / molar mass

Now we will rearrange the formula because we have to calculate the mass.

Mass = number of moles × molar mass

Molar mass of calcium nitrate = 164.088 g/mol

Mass = 11.03 mol × 164.088 g/mol

Mass = 1809.89 g

2. How many molecules are contained in 103.4g of sulfuric acid?

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

Given data:

Number of molecules = ?

Mass of sulfuric acid = 103.4 g

Solution:

Formula:

Number of moles = mass / molar mass

Number of moles = 103.4 g/ 98.079 g/mol

Number of moles = 1.05 mol

1 mole = 6.022 × 10²³ molecules

1.05 mol × 6.022 × 10²³ molecules / 1mol

6.323 × 10²³ molecules of sulfuric acid

3. 3.25 x 1024 molecules of dinitrogen pentoxide would be how many moles?

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

Given data:

Number of molecules of dinitrogen pentoxide = 3.25 × 10²⁴

Moles of dinitrogen pentoxide = ?

Solution:

1 mole = 6.022 × 10²³ molecules

1 mol × 3.25 × 10²⁴ molecules / 6.022 × 10²³ molecules

5.4 moles

4. What would be the mass of 9.03 x 1021 molecules of hydrobromic acid?

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

Given data:

Number of molecules of hydrobromic acid = 9.03 × 10²¹

Mass of hydrobromic acid = ?

Solution:

First of all we will calculate the moles of hydrobromic acid.

1 mole = 6.022 × 10²³ molecules

1 mol × 9.03 × 10²¹ molecules / 6.022 × 10²³ molecules

0.015 moles

Mass of hydrobromic acid:

Mass = number of moles × molar mass

Mass = 0.015 mol × 80.9 g/mol

Mass =1.21 g

5. A sample of iron (III) chloride has a mass of 26.29g. How many moles would this be?

Given data:

Number of moles =?

Mass of iron(III) chloride = 26.29 g

Solution:

Formula:

Number of moles = mass / molar mass

Molar mass of iron chloride = 162.2 g/mol

Now we will put the values in formula.

Moles = 26.29 g/ 162.2 g/mol

Moles = 0.16 g

Answer from: Quest

1.43 x 10^-11 j the guy commented the awnser just making sure u see it .

Answer from: Quest

C) electrons encircling a nucleus with neutrons and protons

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Moles/Mass/Molecules Practice Problem Worksheet

Complete the following problems: