The titration of an impure sample of KHP found that 35.00 mL of 0.050 M NaOH was required to react completely with 0.596 g of sample. What is the percentage of KHP in this sample

59.97%

Explanation:

The equation for the reaction of KPH with NaOH can be given as:

KHC8H4O4 + NaOH→ KNaC8H4O4 + H2O

KHP + NaOH → KNaP +H2O

To get the moles of NaOH.

Moles of NaOH = 0.0350L NaOH×0.050 mol NaOH/1L NaOH

=0.00175 mol NaOH

To get the moles of KHP neutralized by the NaOH.

Moles of KHP=0.00175 mol NaOH × 1 mol KHP/1mol NaOH

=0.00175 mol KHP

we can then  calculate the mass of the KHP.

Mass=0.00175 mol KHP × 204.22 g KHP/1mol KHP

=0.3574 grams of KHP

To calculate the purity of the KHP.

Purity=(mass of pure KHP/mass of impure KHP)×100%

=(0.3574g/0.596g)×100%

=59.97%

58750.08068 is the answer i think