Onsider the reaction, which takes place at a certain elevated temperature CO(g)+NH3(g)⇌HCONH2(g), Kc=0.860 If a reaction vessel initially contains only CO and NH3 at concentrations of 1.00 M and 2.00 M, respectively, what will the concentration of HCONH2 be at equilibrium?

concentration of HCONH2 at equillibrium is 0.5 M

Explanation:

                               CO(g) + NH3(g) ⇌ HCONH2(g)

-vessel iniatial             1             2                 0

concentration

-equillibrium              1-x         2-x               x

concentration

                               

                               0.860 = (1-x)(2-x) / x

                                 

                                 

         concentration of HCONH2 at equillibrium is 0.5 M

the catch is that the top numbers are atomic masses the bottom numbers are the numbers of protons and electrons in an uncharged atom. they are the number of that atoms as you would find them on the periodic table. further, the numbers on the left are used to determine the missing numbers on the right

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer

Compound with sulfer  is bright red