What mass of Ni(CO)4Ni(CO)4 is allowable in a laboratory that is 12 ftft ×× 21 ftft ××11 ftft ? Express your answer using two significant figures.

The answer to the question is

Only up to 1.45×10⁻³ grams of Ni(CO)₄ is allowable in the room

Explanation:

The allowable concentration of Ni(CO)₄ in a room is 1 ppb that is one part per billion, therefore

volume of gas in a room of 12 ft by 21 ft by 11 ft = 2772 ft³

From PV = nRT, n = (P×V)÷(R×T)

in SI units we have  at 1 atm or 101325 Pa, V = ‪78.49 m³   R 3.142 J/mol·K

n = 101325×78.49/(3.142×298.15) = 8489.65 moles

The room can contain 8489.65 moles of  Ni(CO)₄ However allowable concentration is 1 part per billion or

(8489.65/1000000000) moles = 8.49×10⁻⁶ moles

Molar mass of Ni(CO)₄ = 170.73 g/mol

Allowable mass of Ni(CO)₄ = Number of moles × molar mass

= 170.73 g/mol×8.49×10⁻⁶ moles = 1.45×10⁻³ grams

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be