If 35.0 mL of a 0.0500 M HNO3, 35.0 mL of a 0.0600 M KSCN, and 45.0 mL of a 0.0800 M Fe(NO3)3 are combined, what is the initial concentration of SCN- in the mixture?

Explanation:

Chemical equation for the given reaction is as follows.

KSCN is present 35.0 ml of 0.06 M. Hence, we will calculate the total milimoles of as follows.

                  = 2.1 mmoles

Now, we will calculate the total volume in mixture as follows.

      Total volume = (35 + 35 + 45) mL

                             = 115 ml

Hence, initial concentration of will be calculated as follows.

              =

              = 0.0182 M

Thus, we can conclude that the initial concentration of in the mixture is 0.0182 M.

gas

explanation:

smoke is the matter of a gas