What is the molar mass of 31.3g of gas exerting a pressure of 5.71 atm on the
walls of a 3.04 L container at 297 K?

Molar Mass of the gas = 43.9g/mol

Explanation:

The following data were obtained from the question

Mass = 31.3g

P = 5.71 atm

V = 3.04 L

T = 297 K

To solve for the molar mass of the gas, we must first obtain the number of moles of using the ideal gas equation PV =nRT

Where The gas constant R = 0.082atm.L/mol /K

PV = nRT

n = PV /RT

n = (5.71 x 3.04)/(0.082 x 297)

n = 0.7128mol

Recall,

n = Mass /Molar Mass

Molar Mass = Mass / n

Molar Mass = 31.3/0.7128

Molar Mass of the gas = 43.9g/mol

the answer is barium and copper bromide

bcde is the incorrect answer it is a