2b(s) + 3f2(g) 2bf3(g).

which equilibrium expression is correct?

2 B(s) + 3 F₂(g) = 2 BF₃(g)

Kc = products / reagents

Kc = [ BF₃ ]² / [ B ]² . [ F₂ ]³

hope this helps!

The closer the atoms are to becoming ionic the more highly dense the negatively charged side gets.

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