. Determine the standard free energy change, ɔ(G p for the formation of S2−(aq) given that the ɔ(G p for Ag+(aq) and Ag2S(s) are 77.1 k/mole and −39.5 kJ/mole respectively, and the solubility product for Ag2S(s) is 8 10−51.

The standard free energy change of formation of is 92.094 kJ/mol

Explanation:

We are given:

Relation between standard Gibbs free energy and equilibrium constant follows:

where,

= standard Gibbs free energy = ?

R = Gas constant =

T = temperature =

K = equilibrium constant or solubility product =

Putting values in above equation, we get:

For the given chemical equation:

The equation used to calculate Gibbs free change is of a reaction is:  

The equation for the Gibbs free energy change of the above reaction is:

We are given:

Putting values in above equation, we get:

Hence, the standard free energy change of formation of is 92.094 kJ/mol

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the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.