The temperature of a sample of water increases from 30.0 degrees C to 40.0 degrees C as 6540 joules of heat are added. What is the mass of the sample of water?

 166 g

Explanation: q = mC∆T

q = heat = 6940 J

m = mass = ?

C = specific heat of water = 4.184 J/g/deg

∆T = change in temperature = 40.0 - 30.0 = 10.0ºC

6940 J = (m)(4.184J/g/deg)(10 deg)

m = 165.9 g = 166 g

166 g

Explanation:

The equation of specific heat capacity is:

ΔE = mcΔtheta

ΔE = 6540J

c = 4200J/kg°C

Δtheta = 40 - 30 = 10

6540 = m × 4200 × 10

6540 = m × 42000

6540 ÷ 42000 = m

m = 0.15571428...

m = 0.166 kg

m = 166 g

answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.

there are no statements provided but here is why:

sulfur belongs to group 16 because it can be found in nature whether it is in a free or combined state.

hope this