At a particular temparature, the equilibrium constant, Kc for the reaction, 2 NO(g) + 2 H2(g) <=> N2(g) + 2 H2O(g) is 0.7689. Calculate the value of Kc for the reaction 2 N2(g) + 4 H2O(g) <=> 4 NO(g) + 4 H2(g)

Kc= 1.691

Explanation:

The equilibrium given  in this question  along its Kc is:

2 NO(g) + 2 H₂(g) <=> N₂(g) + 2 H₂O(g)     Kc = 0.7689

Now, they are asking us to find the value of the equilibrium constant Kc for:

2 N₂(g) + 4 H₂O(g) <=> 4NO(g) + 4 H₂(g)    Kc=?

This second equation is the reverse of the first multiplied by two. Therefore its equilibrium constant will the inverse square of the first one.

Kc = (  1 / 0.7689 )² = 1.691

Just remeber that the equilibrium constant for the reverse reaction is the inverse of the constant for the forward reaction.

Also if we multiply the coefficients of the balanced equation by a factor, we must raise thje equilibrium constant to the power of that factor.

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

both adhesion and cohesion are attractions.

they are different in that adhesion is the force of attraction between the molecules of two different substances, whereas cohesion is the force of attraction between molecules of the same substance.

possible examples include capillary action, in which the adhesion between water and glass causes the water to rise in a narrow tube against the force of gravity.

because of hydrogen bonding, water is extremely cohesive.

this causes molecules on the surface of water to be drawn inward, which is why drops of water form beads on smooth surfaces.

hope this .