At a particular temperature a 2.00-L flask at equilibrium contains 2.80 ✕ 10-4 mol N2, 2.50 ✕ 10-5 mol O2, and 2.00 ✕ 10-2 mol N2O. Calculate K at this temperature for the following reaction. 2 N2(g) + O2(g) equilibrium reaction arrow 2 N2O(g)

Answer : The value of equilibrium constant (K) is,

Explanation :

First we have to calculate the concentration of

and,

and,

Now we have to calculate the value of equilibrium constant (K).

The given chemical reaction is:

The expression for equilibrium constant is:

Now put all the given values in this expression, we get:

Thus, the value of equilibrium constant (K) is,