How many moles of nitrogen are found in 3.497 x 1020 molecules of Cu(NO3)2?

1.161 * moles of nitrogen

Explanation:

Each cupric nitrate  Cu(NO3)2 molecule will contain 2 atoms of Nitrogen

Given that there are  3.497 x molecules of Cu(NO3)2

So there are 2 * 3.497 x  atoms of nitrogen in 3.497 x molecules of Cu(NO3)2

One mole of nitrogen will contain 6.022 x ( this is the Avogadro number) atoms .

There fore in  2 * 3.497 x atoms we have 2*3.497 x /6.022 x moles of nitrogen

Simplifying this , there are 1.161 * moles of nitrogen

what does the table look like

50.23 i believe is correct but don't quote me on that.