A 6.55 g sample of aniline (C_{6}H_{5}H_{2}, molar mass = 93.13 g/mol) was combusted in a bomb calorimeter. If the temperature rose by 32.9°C, use the information below to determine the heat capacity of the calorimeter.

Heat Capacity of calorimeter is 6.842 kJ/°C

Explanation:

4 C6H5NH2(l) + 35 O2(g) → 24 CO2(g) + 14 H2O(g) + 4 NO2(g)

ΔH°rxn = -1.28 x 10⁴ kJ

4 moles of aniline gives 12800 kJ of heat,

1 mole of aniline will give 12800/4 kJ amount of heat = 3200 kJ

ΔH°rxn for 1 mole of aniline = -3200 kJ

1 mole of aniline weighs 93.13 g/mol

6.55 g of aniline has 6.55/93.13 moles = 0.0703 moles

And this would give off 0.0703 × 3200J amount of heat off

0.0703 × 3200 = 225.1 kJ.

Heat lost by aniline = Heat gained by calorimeter,

Heat lost by aniline = 225.1 kJ

Heat gained by calorimeter = C ΔT = C (32.9)

225.1 = C (32.9)

C = 6.842 kJ/°C

answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.

the solar system used to have much dust particles option no d