When iron rusts, solid iron reacts with gaseous oxygen to form solid iron(III) oxide. Enter a balanced chemical equation for this reaction. Express your answer as a chemical equation. Identify all of the phases in your answer.

The balanced chemical reaction of rusting of solid is given as;

Explanation:

Solid iron + Oxygen gas  →  Iron(III) oxide

Step 1 : Writer 2 in front of Fe(s)

Step 2 : Writer 3 in front of and 2 in front of to balcne the oxygen atom.

Step 3 : Now, iron on product side is more so, write 4 on the place 2 in front of Fe(s).

The balanced chemical reaction of rusting of solid is given as;

According to reaction , 4 moles of solid iron reacts with 3 moles of oxygen gas to give solid compound as product named iron(III) oxide or ferric oxide

43.452

step-by-step explanation:

284 times .153 = 43.452

un recipient conține 6,4 moli de gaz. gazul hidrogen reprezintă 25% din totalul kilometrilor din container. în cazul în care presiunea totală este de 1.24 atm ceea ce este