How much charged is required to reduced 2 moles of cr6+ to cr3+

6e⁻

Explanation:

Charge in reducing 2 mole of Cr⁶⁺ to Cr³⁺

              Cr⁶⁺   +      xe⁻           →       Cr³⁺

The numbers 6+ and 3+ on the chromium atoms are the oxidation number of the atom.

It shows the number of electrons that has been lost by chromium in an oxidation state.

         Cr⁶⁺ shows that it has lost 6 electrons. When an atom loses electrons, the number of protons becomes more. This makes it positively charged in nature.

      This analogy goes for Cr³⁺

 Therefore, in going from reactants to products, chromium

                                6+      →    3+

 In this kind of expression, the number of atoms must be conserved and the charges too;

                        2Cr⁶⁺   +      xe⁻           →       2Cr³⁺

    given 2 moles of Cr;

               To balance the charge;

               2(6+) + x(-) = 2(3+)

                   12 - x = 6

                          x  = 6

A charge of 6e⁻ is required to reduce 2 mole of Cr⁶⁺ to Cr³⁺

frequency, z, and the collision density, z, in carbon dioxide (co2), r 180 pm at 30 °c and 120 kpa