G A hydrogen atom initially in the n = 4 states emits a photon and makes a transition to the n = 2 level. What is the wavelength of the photon in nm? (report 4 sig figs) What part of the electromagnetic spectrum does this correspond to?

The wavelength of the photon is 486.2 nm and it lies in the visible region

Explanation:

To calculate the wavelength of light, we use Rydberg's Equation:

Where,

= Wavelength of radiation

= Rydberg's Constant =

= Higher energy level = 4

= Lower energy level = 2

Putting the values in above equation, we get:

Converting this into nanometers, we use the conversion factor:

So,

As, the range of wavelength of visible light is 400 nm - 700 nm. So, the wavelength of the given photon lies in the visible region

Hence, the wavelength of the photon is 486.2 nm and it lies in the visible region

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation:

1. they vary with a higher number because boiling is way hotter than melting