Amount of I- reacted in Reaction (1) in each case will be = Amount of S2O3-2 reacted in Reaction (3) = moles S2O3-2 in (3) = moles of I- reacted in (1) moles I- reacted  Liter reaction mixture = M I- reacted = - [I-1] = - [ ] Average Rate of Reaction = -

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.