1. What is the rate law and the value of the rate constant for the reaction: 2 AB2 + C -- CB What is the order for each reactant and the overall order for the reaction. Write correct label for ""k"" rate constant. Trail [AB2] [C] Rate of CB 1 1.0 1.0 1.4*10-7 M/min 2 0.5 1.0 3.5*10-8 M/min 3 1.0 2.0 5.5*10-7 M/min

Answer :

The rate law becomes:

The value of the rate constant 'k' for this reaction is

The order of each reactant is, 2

Overall order of reaction = 4

Explanation :

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

Rate law expression for the reaction:

where,

a = order with respect to

b = order with respect to

Expression for rate law for first observation:

....(1)

Expression for rate law for second observation:

....(2)

Expression for rate law for third observation:

....(3)

Dividing 2 from 1, we get:

Dividing 1 from 3, we get:

Thus, the rate law becomes:

Now, calculating the value of 'k' by using any expression.

Hence, the value of the rate constant 'k' for this reaction is

The order of each reactant is, 2

Overall order of reaction = a + b = 2 + 2 = 4

answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.