What is the atom inventory for the following equation after it is properly balanced? NaOH + CuCl2 Imported Asset NaCl + Cu(OH)2 Reactants: Na = 1, O = 1, H = 1, Cu = 2, Cl = 2; Products: Na = 1, O = 1, H = 1, Cu = 2, Cl = 2 Reactants: Na = 1, O = 2, H = 2, Cu= 2, Cl= 2; Products: Na = 1, Cl = 1, Cu = 2, O = 2, H = 2 Reactants: Na = 1, O = 1, H = 1, Cu = 1, Cl = 21; Products: Na = 1, O = 1, H = 1, Cu = 1, Cl = 2 Reactants: Na = 2, O = 2, H = 2, Cu = 1, Cl = 2; Products: Na = 2, Cl = 2, Cu = 1, O = 2, H = 2

Reactants: Na = 2, O = 2, H = 2, Cu = 1, Cl = 2;

Products: Na = 2, Cl = 2, Cu = 1, O = 2, H = 2

Explanation:

NaOH + CuCL2 —> NaCl + Cu(OH)2

The balanced equation can be achieved by doing the following:

There are 2 oxygen and 2 hydrogen atom on the right side. This is balanced by putting 2 in front of NaOH as shown below:

2NaOH + CuCL2 —> NaCl + Cu(OH)2

This makes Na to be unbalanced. Now to balance Na, put 2 in front of NaCl as illustrated below

2NaOH + CuCL2 —> 2NaCl + Cu(OH)2

Now the equation is balanced.

Reactants: Na = 2, O = 2, H = 2, Cu = 1, Cl = 2

Products: Na = 2, Cl = 2, Cu = 1, O = 2, H = 2

it's all four options.