What volume of 0.100 MM HClO4HClO4 solution is needed to neutralize 44.00 mLmL of 8.80×10−2 MM NaOHNaOH ?

Volume of acid = 38.7 mL.

To neutralize 44 mL of NaOH

Explanation:

Formula for neutralization an acid and a base is:

M acid . Volume of acid = M base . Volume of base

Let's replace the data given:

0.1 M . Volume of acid = 8.80×10⁻² M . 44 mL

Volume of acid = (8.80×10⁻² M . 44 mL) / 0.1M → 38.7 mL

We need 38.72 mL of the 0.100 M HClO4 solution

Explanation:

Step 1: Data given

Molarity of the HClO4 solution = 0.100 M

Volume of the 8.80 *10^-2 M NaOH solution = 44.00 mL

Step 2: Calculate the volume of HClO4

HClO4 + NaOH ⇒ NaClO4 + H2O

b*Ca*Va =a*Cb*Vb

⇒ with b = the coefficient of NaOH = 1

⇒ with Ca = the concentration of HClO4 = 0.100 M  

⇒ with Va = The volume of HClO4 = TO BE DETERMINED

⇒ with a = the coefficient of HClO4 = 1

⇒ with Cb = the molarity of NaOH = 8.80 *10^-2 M

⇒ with Vb = the volume of NaOH = 44.00 mL = 0.044 L

1 * 0.100 * Va = 1 * 8.80*10^-2 *0.044

Va = 0.03872 L = 38.72 mL

We need 38.72 mL of the 0.100 M HClO4 solution

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