Write the balanced neutralization reaction that occurs between H 2 SO 4 and KOH in aqueous solution. Phases are optional.

H2SO4 + 2KOH —> K2SO4 + 2H2O

Explanation:

The predicted equation is given as shown below:

H2SO4 + KOH —> K2SO4 + H2O

Now we need to balance the equation. To do this, put 2 in front of KOH, we have:

H2SO4 + 2KOH —> K2SO4 + H2O

Now we need to balance H20. This can be achieved by putting 2 in front of H2O., as shown below

H2SO4 + 2KOH —> K2SO4 + 2H2O

From above, we see that each element are balanced on both side

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6

c- cold periods in earth's history during which glaciers covered much of the surface.

explanation: