Calculate the osmotic pressure of a magnesium citrate laxative solution containing 25.5 g of magnesium citrate in 244 mL of solution at 37 ∘C (approximate body temperature). Assume complete dissociation of the ionic compound.

The answer to your question is π = 12.47 atm

Explanation:

Data

mass of Magnesium citrate = 25.5 g

volume of solution = 244 ml

temperature = 37°C

molar mass C₆H₆MgO₇ = (12 x 6) + (1 x 6) + (24 x 1) + (16 x 7) = 214 g

Osmotic pressure = π = ?

Process

1.- Calculate the moles of magnesium citrate

                         214 grams 1 mol

                          25.5 grams  x

                           x = (25.5 x 1)/214

                           x = 0.119

2.- Calculate molarity

Molarity = moles/volume

Molarity = 0.119/0.244

Molarity = 0.49

3.- Calculate osmotic pressure

π = MRT

π = (0.49)(0.0821)(37 + 273)

π = (0.49)(0.0821)(310)

π = 12.47 atm

answer: c.

explanation: