A 2.0 cm diameter faucet tap fills a 2.5 x 10-2 m3 container in 30.0 s. What is the speed at which the water leaves the faucet?

                      Speed of Water  =  2.652 ms⁻¹

Explanation:

Step 1: Calculate the Radius of the Faucet:

                       Radius  =  Diameter / 2

                       Radius  =  2 cm / 2

                       Radius =  1 cm or 0.01 m

Step 2: Calculate Cross-Section Area of Faucet:

                       Area  =  π r²

                       Area  =  π (0.01 m)²

Step 3: Calculate the Flow Rate (Q) as;

                       Q  =  2.5 × 10⁻² m³ / 30 s

                       Q  =  8.33 × 10⁻⁴ m³/s

Step 4: Calculate Speed of water as;

                       Speed of Water  =  Flow Rate / Cross-Section Area

Putting values,

                       Speed of Water  =  8.33 × 10⁻⁴ m³/s / π (0.01 m)²

                       Speed of Water  =  8.33 × 10⁻⁴ m³/s / 3.14 × 0.0001 m²

                       Speed of Water  =  8.33 × 10⁻⁴ m/s / 0.000314

                        Speed of Water  =  2.652 ms⁻¹

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.