Start with 100.00 mL of 0.10 M acetic acid, CH3COOH. The solution has a pH of 2.87 at 25 oC. a) Calculate the Ka of acetic acid at 25 oC. b) Determine the percent dissociation for the solution.

a) The of acetic acid at is

b) The percent dissociation for the solution is

Explanation:

 cM              0             0

So dissociation constant will be:

Give c= 0.10 M and = ?

Also

Putting in the values we get:

b)  

specific gravity is the density of a substance divided by the density of water. since (at standard temperature and pressure) water has a density of 1 gram/cm3, and since all of the units cancel, specific gravity is usually very close to the same value as density

so "c" is the answer

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