How many grams of Na 2 CO 3 are present in 21.0 mL of a solution that is 36.0 % Na 2 CO 3 by mass? The density of the solution is 1.12 g / mL .

The answer to your question is  8.46 g of Na₂SO₄

Explanation:

Data

mass of Na₂CO₃ = ?

volume = 21 ml

percent by mass = 36%

density = 1.12 g/ml

Process

1.- Calculate the mass of the solution

    density = mass / volume

solve for mass

    mass = density x volume

     mass = 1.12 x 21

     mass = 23.52 g

2.- Calculate the mass of Na₂CO₃

Percent by mass = (mass of Na₂SO₄ / mass of solution) x 100

Solve for mass of Na₂SO₄

               mass of Na₂SO₄ = Percent by mass x mass of solution/100  

               mass of Na₂SO₄ = 36 x 23.52/100

               mass of Na₂SO₄ = 8.46 g

fire could start, buildings collapsing, and ash falling from the sky.

explanation:

this is because the buildings or plants could catch on fire and the buildings would most likely collapse. lastly ash would fall because all the burning would cause ash to fall from the sky.

hope this .

the answer is the first option

explanation:

just googled it m8. not that hard

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