The specific heat of a certain type of metal is 0.128 J / (g ⋅ ∘ C). What is the final temperature if 305 J of heat is added to 93.4 g of this metal, initially at 20.0 ∘ C?

Final T° is 45.5°C

Explanation:

Formula for calorimetry is:

Q = m . C .  ΔT , where

ΔT = Final T° - Initial T°

C = Specific heat

m = mass

Let's replace with the data given

305 J = 93.4 g . 0.128 J/g°C . (Final T° - 20°C)

305 J / 93.4 g . 0.128 J/g°C  = Final T° - 20°C

25.5°C = Final T° - 20°C → Final T° = 25.5°C + 20°C = 45.5°C

radioactive decay occurs in unstable atomic nuclei – that is, ones that don't have enough binding energy to hold

the nucleus together due to an excess of either protons or neutrons.

the dependant variable is spilled water

the independent is the heat