What molal concentration of KOH(aq) has the same freezing point as 0.4 m Al(NO3)3(aq)? Enter only a numerical answer. Do not include units.

The molal concentration of KOH (aq) is 0.8

Explanation:

Depression in freezing point:

where,

= freezing point of solution

= freezing point of solvent

= freezing point constant

m = molality

i = Van't Hoff factor = number of ions produced on dissociation

For i =2 as

For i =4 as

Now put all the given values in the above formula, we get:

For 0.4

For KOH

Thus molal concentration of KOH (aq) is 0.8

since the atomic number is the number of protons in the nucleus, as we move to the left on the periodic table, the electrostatic pull between the nucleus and the valence electron shell decreases. as we move down a group (vertical column), the valence shell energy level gets further and further from the nucleus.

i'm assuming that it's c.) red bank..