A 0.36 L balloon at 23.6 oC and 1050 mm Hg is placed in new conditions of standard temperature and pressure. What will be the new volume of the balloon?

0.46 L is the new volume of the balloon

Explanation:

When the moles of a gas remain constant we have this situation for these conditions

P1 . V1 /T1 = P2 . V2/ T2

First of all we convert the mmHg to atm

1050 mmHg . 1 atm / 760 mmHg =1.38 atm

We also need absolute T°C

T° K = T°C + 273 → 23.6°C + 273 = 296.6 K

STP → 1 atm = P ; 273 K = T

Now we can replace the values:

1.38 atm .  036 L / 296.6K = 1 atm . V2 / 273K

(1.38 atm .  036 L / 296.6K) . 273 K =   1 atm . V2

( 1.38 atm .  036 L / 296.6K) . 273K) / 1 atm = V2 → 0.46 L

the answer is either b or c

answer is: c. the experiment shows that the red substance experienced a chemical change.

this is chemical change (chemical reaction), because two new substances are formed (metalig liquid and gas), the atoms are rearranged and the reaction is followed by an energy change.

this is example of chemical decomposition.

chemical decomposition (analysis) is the separation of a single chemical compound into its two or more elemental parts or to simpler compounds.  

chemical decomposition is opposite of chemical synthesis.