The decomposition of hydrogen peroxide in dilute sodium hydroxide at 20 °C is first order in H2O2. H2O2(aq)H2O(l) + ½ O2(g) During one experiment it was found that the H2O2 concentration dropped from 5.16×10-2 M at the beginning of the experiment to 1.95×10-2 M in 832 min. What is the value of the rate constant for the reaction at this temperature? min-1

The rate constant is 1.98×10^-3 min^-1

Explanation:

The reaction follows a first order

Rate = k[H2O2] = change in concentration of H2O2/time

Initial concentration of H2O2 = 5.16×10^-2 M

Concentration of H2O2 in 832 min = 1.95×10^-2 M

Change in concentration = 5.16×10^-2 - 1.95×10^-2 = 3.21×10^-2 M

Time = 832 min

1.95×10^-2k = 3.21×10^-2/832

k = 3.86×10^-5/1.95×10^-2 = 1.98×10^-3 min^-1

ca has a crystalline lattice with positive ions (since it is a metal, metals are positively charged) and electrons flow freely in its structure since the ca atoms have a large nuclear radius so the electrons are not tightly held, therefore the electrons can flow freely since they are not being highly attracted by the nucleus. moreover, one of the properties of metals are that they are conductors of electricity, thus proving ca is the element.