1) How many grams of carbon dioxide are produced at the same time as 360 g of water vapor in the
burning of ethane?
2C2H6 + 702 > 4CO2 + 6H2O

3520 g of CO₂

Explanation:

2C₂H₆ + 70₂ → 4CO₂ + 6H₂O

molar ratio of the above reaction is;

2 : 7 → 4 : 6

2 moles of C₂H₆ will form 6 moles of H₂O

Thus, 1 mole of C₂H₆ will form 3 moles of H₂O

mass of H₂O = 360 g

molecular weight of H₂O = 18 g/mol

molar mass = mass ÷ molecular weight = 360÷18 = 20 moles

Total number of moles of H₂O formed = 6 * 20 moles = 120 moles

Number of moles of C₂H₆ reacted = 120 moles ÷ 3 = 40 moles

molar ratio of C₂H₆ to CO₂ = 1 : 2

Thus, number of moles of CO₂ formed = 2 * 40 moles = 80 moles

molecular weight of CO₂ = 44 g/mol

mass of CO₂ formed = number of moles x molecular weight = 80 * 44 = 3520 g

some sources quote the lethal dose, for an average 170lbs opiate-naive individual is between 75 and 375 mg