2. Solve the equation x16 - 2x15 - x14 - 4x13 – x12 - 2x11 - x10 = 0 in the real number system.
Ox=-1 with multiplicity 2. x=1 with multiplicity +
Dy=0 with multiplicity 10. x = -1 with multiplicity 3. = 1 with multiplicity 3
Ox=0 with multiplicity 10, x=-1 with multiplicity 2. x = 1 with multiplicity 4
Ox=0 with multiplicity 10.x=-1 with multiplicity 4.x = 1 with multiplicity 2
Answers: 2
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The molecular weight of carbon dioxide, co2, is 44.00 amu, and the molecular weight of nitrous dioxide, no2, is 46.01 amu, so no2 diffuses co2
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2. Solve the equation x16 - 2x15 - x14 - 4x13 – x12 - 2x11 - x10 = 0 in the real number system.
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