A mole of gas at 0.0oC and 760. torr occupies 22.4 L. What is the volume of this gas at 25.oC and 760. torr

24.45 L

Explanation:

From General gas equation,

PV/T = P'V'/T' Equation 1

Where P = initial pressure, V = Initial volume, T = Initial Temperature, P' = Final pressure, V' = Final Volume, T' = Final Temperature.

make V' the subject of the equation.

V' = PVT'/(TP') Equation 2

Given: P = 760 torr, V = 22.4 L, T = 0 °C = (0+273) = 273 K, T' = 25 °C = (25 + 273) = 298 K, P' = 760 torr

Substitute into equation 2

V' = 760(22.4)(298)/(760×273)

V' = 24.45 L.

Hence the volume of the gas = 24.45 L

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