Chemistry, 11.02.2020 23:31 alyssaboosiefkes
The normal boiling point of mercury (Hg) is 356.7 °C. What is the vapor pressure of mercury at 322 °C? (∆Hvap = 58.51 kJ/mol)
Answers: 2
![\ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}[\frac{1}{T_1}-\frac{1}{T_2}]](/tpl/images/0507/4473/b9a49.png)
= initial pressure which is the pressure at normal boiling point = 1 atm
= final pressure which is vapor pressure of mercury = ?
= Enthalpy of vaporization = 58.51 kJ/mol = 58510 J/mol (Conversion factor: 1 kJ = 1000 J)
= initial temperature which is normal boiling point = ![356.7^oC=[356.7+273]K=629.7K](/tpl/images/0507/4473/bb64c.png)
= final temperature = ![322^oC=[322+273]K=595K](/tpl/images/0507/4473/9848f.png)
![\ln(\frac{P_2}{1})=\frac{58510J/mol}{8.314J/mol.K}[\frac{1}{629.7}-\frac{1}{595}]\\\\\ln P_2=-0.6517atm\\\\P_2=e^{-0.6517}=0.521atm](/tpl/images/0507/4473/24635.png)
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The normal boiling point of mercury (Hg) is 356.7 °C. What is the vapor pressure of mercury at 322 °...
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