If 3.0 liters of oxygen gas react with excess carbon monoxide at STP, how many liters of carbon dioxide can be produced under the same conditions?2 CO (g) + O2 (g) ---> 2 CO2 (g)

a. 1.5 L
b. 3.0 L
c. 4.5 L
d. 6.0 L,

The volume of CO2 produced is 6.0 L (option D)

Explanation:

Step 1: Data given

Volume of oxygen = 3.0 L

Carbon monoxide = CO = in excess

Step 2: The balanced equation

2 CO (g) + O2 (g) → 2 CO2 (g)

Step 3: Calculate moles of O2

1 mol of gas at STP = 22.4 L

3.0 L = 0.134 moles

Step 3: Calculate moles of CO2

For 2 moles CO we need 1 mol of O2 to produce 2 moles of CO2

For 0.134 moles O2 we'll have 2*0.134 = 0.268 moles CO2

Step 4: Calculate volume of CO2

1 mol = 22.4 L

0.268 mol = 22.4 * 0.268 = 6.0 L

The volume of CO2 produced is 6.0 L

it's all four options.