The molar enthalpy of vaporization (∆Hvap) for ammonia (NH3) is 23.3 kJ/mol (at −33.3 °C). How much energy is required to evaporate 100. g of ammonia at this temperature?

some sources quote the lethal dose, for an average 170lbs opiate-naive individual is between 75 and 375 mg

it is stable as it is in group 0 which have full outer shells of electrons

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol